ln(x+1)ln(x)+ln(x^2)=1

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Solution for ln(x+1)ln(x)+ln(x^2)=1 equation: 


Simplifying
ln(x + 1) * ln(x) + ln(x2) = 1

Reorder the terms:
ln(1 + x) * ln(x) + ln(x2) = 1

Reorder the terms for easier multiplication:
ln * ln * x(1 + x) + ln(x2) = 1

Multiply ln * ln
l2n2 * x(1 + x) + ln(x2) = 1

Multiply l2n2 * x
l2n2x(1 + x) + ln(x2) = 1
(1 * l2n2x + x * l2n2x) + ln(x2) = 1
(1l2n2x + l2n2x2) + ln(x2) = 1

Multiply ln * x2
1l2n2x + l2n2x2 + lnx2 = 1

Reorder the terms:
lnx2 + 1l2n2x + l2n2x2 = 1

Solving
lnx2 + 1l2n2x + l2n2x2 = 1

Solving for variable 'l'.

Reorder the terms:
-1 + lnx2 + 1l2n2x + l2n2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + lnx2 + 1l2n2x + l2n2x2 = 0

The solution to this equation could not be determined.

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